A note on the diophantine equation $(x^k-1)(y^k-1)^2=z^k-1$

HIGHLIGHTS

• What: The authors focus particularly on the case where k is a prime number in Eq . Some related questions For the Diophantine equation (xk - 1)(y k - 1)2=z k - 1, the authors show that there is no positive integer 1 solutions satisfying 1 and amp;lt; x ≤ y or 1 and amp;lt; y and amp;lt; x ≤ ((y k - 1)k-2 + 1) k.
• Who: Yangcheng Li from the School of Mathematical Sciences, South China Normal University have published the research work: A note on the Diophantine equation (x^k-1)(y . . .
  

   

  

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