HIGHLIGHTS
SUMMARY
By an application of the operator Daα to Waα(φ1, φ2 ), the authors obtain Daα(Waα(φ1, φ2 ))(t )=Daα(φ1(t )Daαφ2 (t ) - φ2 (t )Daαφ1(t ))=Daαφ1(t )Daαφ2 (t ) + φ1(t )Daα(Daαφ2 (t )) - Daαφ2 (t )Daαφ1(t ) - φ2 (t )Daα(Daαφ1(t ))=φ1(t )Daα(Daαφ2 (t )) - φ2 (t )Daα(Daαφ1(t )). Daα(Waα(φ1, φ2 ))(t )=φ1(t )( -p(t )Daαφ2 (t ) - q (t )φ2 (t )) - φ2 (t )( -p(t )Daαφ1(t ) - q (t )φ1(t ))=- φ1 . . .
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